A bat hits a moving baseball. If the bat delivers a net eastward impulse of 1.5 N-s and the ball starts with an initial horizontal velocity of 3.8 m/s to the west and leaves with a 4.9 m/s velocity to the east, what is the mass of the ball (in grams)? (NEVER include units in the answer to a numerical question.)

Respuesta :

Answer:

The mass of the ball is 5866 g.

Explanation:

Given that,

Impulse = 1.5 N.s

Velocity to the west = 3.8 m/s

Velocity to the east = 4.9 m/s = -4.9 in to the west

We need to calculate the mass of the ball

Using formula of impulse

[tex]I = p_{i}-P_{f}[/tex]

[tex]I=m(v_{i}-v_{f})[/tex]

[tex]m=\dfrac{v_{i}-v_{f}}{I}[/tex]

Where, [tex]v_{i}[/tex] = initial velocity

[tex]v_{f}[/tex] =final velocity

m = mass of ball

Put the value into the formula

[tex]m=\dfrac{3.9-(-4.9)}{1.5}[/tex]

[tex]m=5.866\ kg[/tex]

[tex]m = 5866\ g[/tex]

Hence, The mass of the ball is 5866 g.