A company produces steel rods. The lengths of the steel rods are normally distributed with a mean of 236.8-cm and a standard deviation of 1.3-cm. For shipment, 29 steel rods are bundled together. Find the probability that the average length of a randomly selected bundle of steel rods is between 236.5-cm and 236.7-cm. P(236.5-cm < M < 236.7-cm) =

Respuesta :

Transform M to the standard normally distributed random variable Z via

[tex]Z=\dfrac{M-\mu_M}{\sigma_M}[/tex]

where [tex]\mu_M[/tex] and [tex]\sigma_M[/tex] are the mean and standard deviation for [tex]M[/tex], respectively. Then

[tex]P(236.5<M<236.7)=P(-0.2308<Z<-0.0769)\approx\boxed{0.0606}[/tex]

Answer:

0.0606.                        .                

hope this helps