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A flat coil of wire consisting of 20 turns, each with an area of 50 cm2, is positioned perpendicularly to a uniform magnetic field that increases its magnitude at a constant rate from 2.0 T to 6.0 T in 2.0 s. If the coil has a total resistance of 0.40 Ω, what is the magnitude of the induced current

Respuesta :

Answer:

i = 0.5 A

Explanation:

As we know that magnetic flux is given as

[tex]\phi = NBA[/tex]

here we know that

N = number of turns

B = magnetic field

A = area of the loop

now we know that rate of change in magnetic flux will induce EMF in the coil

so we have

[tex]EMF = NA\frac{dB}{dt}[/tex]

now plug in all values to find induced EMF

[tex]EMF = (20)(50 \times 10^{-4})(\frac{6 - 2}{2})[/tex]

[tex]EMF = 0.2 volts[/tex]

now by ohm's law we have

[tex]current = \frac{EMF}{Resistance}[/tex]

[tex]i = \frac{0.2}{0.40} = 0.5 A[/tex]