If its acceleration is constant, then it is equal to the jet's average velocity, given by
[tex]a=a_{\rm ave}=\dfrac{\Delta v}{\Delta t}[/tex]
Then it takes
[tex]17.7\dfrac{\rm m}{\mathrm s^2}=\dfrac{233\frac{\rm m}{\rm s}-119\frac{\rm m}{\rm s}}{\Delta t}\implies\Delta t=\boxed{6.44\,\mathrm s}[/tex]
Answer:
The time taken by the jet is 6.44 seconds.
Step-by-step explanation:
It is given that,
Acceleration of the jet, [tex]a=17.7\ m/s^2[/tex]
Initial velocity of the jet, u = 119 m/s
Final velocity of the jet, v = 233 m/s
Acceleration of an object is given by :
[tex]a=\dfrac{v-u}{t}[/tex]
[tex]t=\dfrac{v-u}{a}[/tex]
[tex]t=\dfrac{233-119}{17.7}[/tex]
t = 6.44 seconds
So, the time taken by the jet is 6.44 seconds. Hence, this is the required solution.
