Answer:
1/ K times
Explanation:
The capacitance of a parallel plate capacitor is given by
[tex]C = \frac{\varepsilon _{0}A}{d}[/tex]
Where, A be the area of plates and d be the distance between the plates.
When a dielectric is inserted between the plates, the new capacitance is
[tex]C' = \frac{k\varepsilon _{0}A}{d}=kC[/tex]
The charge remains same.
As we know that
q = C V
The capacitance becomes KC so, to keep the charge remains same the potential difference should be 1 / K times.
V' = V / K
