Answer:
p = 8N/mm2
Explanation:
given data ;
diameter of cylinder = 150 mm
thickness of cylinder = 6 mm
maximum shear stress = 25 MPa
we know that
hoop stress is given as =[tex]\frac{pd}{2t}[/tex]
axial stress is given as =[tex]\frac{pd}{4t}[/tex]
maximum shear stress = (hoop stress - axial stress)/2
putting both stress value to get required pressure
[tex]25 = \frac{ \frac{pd}{2t} -\frac{pd}{4t}}{2}[/tex]
[tex]25 = \frac{pd}{8t}[/tex]
t = 6 mm
d = 150 mm
therefore we have pressure
p = 8N/mm2
