Respuesta :
Answer:
Required mass of sand is 20 kg
Explanation:
Given:
Mass of the plank = 25 kg
Distance of the Center of gravity of the Plank from the fulcrum = [tex]\frac{2}{2}-0.50 = 0.5m[/tex]
Distance of the Center of gravity of the sand box from the fulcrum = [tex]\frac{2}{2}-\frac{0.75}{2}= 0.625m[/tex]
Balancing the torque due to the plank and the sand box with respect to the fulcrum
Torque = Force × perpendicular distance
thus, we get
(25 × g) × 0.5 = weight of sand × 0.625
where, g is the acceleration due to gravity
or
(25 × g) × 0.5 = (mass of sand × g) × 0.625
or
mass of sand = 20 kg
Hence, the required mass of the sand is 20 kg
Answer:
20 Kg mass of sand should be put into the box so that the plank balances horizontally on a fulcrum placed horizontally on a fulcrum placed just below its midpoint.
Explanation:
Use the second condition of equilibrium.
[tex]$\sum} \tau=0$[/tex]
[tex]MgL-$M g x_{c m}=0$[/tex]
[tex]$M=\frac{m x_{c m}}{L}[/tex]
[tex]=\frac{25(0.50)}{0.625}[/tex]
[tex]=20 \mathrm{~kg}$[/tex]
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