Answer:
[tex]\frac{2}{7}+\sqrt{121}[/tex]
Step-by-step explanation:
Since, a real number is called rational number if it can be expressed in the form of [tex]\frac{p}{q}[/tex],
Where, p and q are integers,
S.t. q ≠ 0,
If the number is not a rational number then it is irrational,
Now, the sum or difference of two rational numbers is a rational number,
While, the sum or difference of a rational number and an irrational number is an irrational number.
∵ √18, √11 and [tex]\pi[/tex] are irrational numbers,
Also, [tex]\frac{5}{9}[/tex], [tex]\sqrt{16}[/tex] and [tex]\frac{3}{10}[/tex] are rational number,
[tex]\implies \frac{5}{9}+\sqrt{18},\pi+\sqrt{16}, \frac{3}{10}+\sqrt{11}\text{ are irrational numbers}[/tex]
Now,
[tex]\frac{2}{7}\text{ and }\sqrt{121}\text{ are rational numbers}[/tex]
Hence,
[tex]\frac{2}{7}+\sqrt{121}\text{ is rational number}[/tex]
