Answer:0.2338KWh
Explanation:
Given
mass of air[tex]\left ( m\right )[/tex]=15kg
Initial Temperature[tex]\left ( T_i\right )=25^{\circ}C[/tex]
Final Temperature[tex]\left ( T_f\right )=95^{\circ}C[/tex]
pressure is constant 300 KPa
heat loss =60 KJ
Enthalpy at [tex]25^{\circ}C\ is\ h_1=298.2KJ/kg[/tex]
Enthalpy at [tex]95^{\circ}C\ is\ h_2=350.49KJ/kg[/tex]
[tex]h_2-h_1=52.29 KJ/kg[/tex]
and for 15 kg air
[tex]\Delta h=784.35 KJ[/tex]
Thererfore net heat input=[tex]\Delta h+60[/tex]
=784.35+60=844.35KJ
=[tex]844.35\times 0.000277=0.2338KWh[/tex]