Answer:
The surface area of the structure is [tex]SA=2,500\pi\ m^{2}[/tex]
Step-by-step explanation:
we know that
The surface area of a sphere is equal to
[tex]SA=4\pi r^{2}[/tex]
In this problem we have
[tex]r=50/2=25\ m[/tex] -----The radius is half the diameter
substitute
[tex]SA=4\pi (25)^{2}[/tex]
[tex]SA=2,500\pi\ m^{2}[/tex]
