Answer:
245°C
Explanation:
Properties of steam at 90°C
[tex]s_f= 1.19\frac{KJ}{Kg-K} , s_g=7.47\frac{KJ}{Kg-K}[/tex]
[tex]v_f=0.001035\frac{m^3}{Kg} ,v_g=2.39\frac{m^3}{Kg}[/tex]
to find dryness fraction
[tex]v=v_f+x(v_g-v_f)\frac{m^3}{Kg}[/tex]
v is the specific volume,[tex]v=\dfrac{1.8}{32.933}\dfrac{m^3}{kg}[/tex]
0.0546=0.001035+x(2.39-0.001035)
x=0.0224
When all water will covert in vapor steam then
volume[tex]vapor steam=0.0546\dfrac{m^3}{kg}[/tex]
[tex]v_g=0.0546\dfrac{m^3}{kg}[/tex]
Now from steal table we can say that temperature corresponding to vapor volume [tex]v_g=0.0546\dfrac{m^3}{kg}[/tex] is 245°C.
