At time t0 = 0 the mass happens to be at y0 = 4.05 cm and moving upward at velocity v0 = +4.12 m/s. (Mind the units!) Calculate the amplitude A of the oscillating mass. Answer in units of cm.

Respuesta :

Answer:

A = 5.727 cm

Explanation:

at time t = 0s the displacement of mass is 4.05 cm and velocity 4.12 m/s

we know that velcoity for simple harmonic motion is given as

[tex]v_o = \omega \sqrt {A^2 - Y_O^2}[/tex]

W KNOW THAT

[tex]\omega = \frac{v_0}{Y_o}[/tex]

Therefore we  get

[tex]Y_O^2 = A^2 - Y_O^2[/tex]

[tex]A =\sqrt 2 * Y_O[/tex]

[tex]A =\sqrt 2 * 4.05\\[/tex]

A = 5.727 cm