Respuesta :
Answer:
A: 0
B: There is one real root with a multiplicity of 2.
Step-by-step explanation:
[tex]\bf{x^2+2x+1=0}[/tex]
A:
The discriminant of the quadratic equation can be found by using the formula: [tex]b^2-4ac[/tex].
In this quadratic equation,
- a = 1
- b = 2
- c = 1
I found these values by looking at the coefficient of [tex]x^2[/tex] and [tex]x[/tex]. Then I took the constant for the value of c.
Substitute the corresponding values into the formula for finding the discriminant.
- [tex]b^2-4ac[/tex]
- [tex](2)^2-4(1)(1)[/tex]
Simplify this expression.
- [tex](2)^2-4(1)(1)= \bf{0}[/tex]
The answer for part A is [tex]\boxed{0}[/tex]
B:
The discriminant tells us how many real solutions a quadratic equation has. If the discriminant is
- Negative, there are no real solutions (two complex roots).
- Zero, there is one real solution.
- Positive, there are two real solutions.
Since the discriminant is 0, there is one real root so that means that the first option is correct.
The answer for part B is [tex]\boxed {\text{There is one real root with a multiplicity of 2.}}[/tex]
Answer:
A: 0
B: There is one real root with a multiplicity of 2 .
Step-by-step explanation:
Given a quadratic equation:
[tex]ax^2+bx+c=0[/tex]
You can find the Discriminant with this formula:
[tex]D=b^2-4ac[/tex]
In this case you have the following quadratic equation:
[tex]x^2+2x+1=0 [/tex]
Where:
[tex]a=1\\b=2\\c=1[/tex]
Therefore, when you substitute these values into the formula, you get that the discriminant is this:
[tex]D=(2)^2-4(1)(1)\\\\D=0[/tex]
Since [tex]D=0[/tex], the quadratic equation has one real root with a multiplicity of 2 .