Answer:
Depth of well 3.06m
Explanation:
We know that for a pipe closed at one end the frequencies are in ratios if 1:2:3:5:7.... to the fundamental frequency
In our case the given frequencies are in the ratio of
a)[tex]\frac{140}{196}=\frac{5}{7}[/tex]
b) [tex]\frac{196}{252}=\frac{7}{9}[/tex]
Thus the fundamental frequency can be calculated as [tex]140Hz=5n[/tex]
[tex]\therefore n=\frac{140}{5}=28Hz[/tex]
Now we know that
[tex]\lambda_{1}=4l\\\\\frac{v}{f}=4l\\\\l=\frac{v}{4f}[/tex]
Applying values we get
[tex]L=3.06m[/tex]