Answer:
[tex]\omega_O = 0.16 rad /sec[/tex]
Q = 0.24
Explanation:
given data:
resonant angular frequency is given as \omega_O = \frac{1}{\sqrt{LC}}
where L is inductor = 150 mH
C is capacitor = 0.25\mu F
[tex]\omega = \frac{1}{\sqrt{150*10^{6}*0.25*10^{-6}}}}[/tex]
[tex]\omega_O = 0.16 rad /sec[/tex]
QUALITY FACTOR is given as
[tex]Q = \frac{1}{R}{\sqrt\frac{L}{C}}[/tex]
Putting all value to get quality factor value
Q =[tex] \frac{1}{1000}{\sqrt\frac{150*10^{6}}{0.25*10^{-6}}}[/tex]
Q = 0.24
