Given:
R = 13 Ω
L = 46 mH
V = 240 V(rms)
f = 60 Hz
Formula used:
[tex]I_{L} = \frac{V}{R + jX_{L} }[/tex]
[tex]X_{L} = 2\pi fL[/tex]
Solution:
Now, using the above formula for [tex]X_{L}[/tex]:
[tex]X_{L} = 2\pi\times 60\times 46\times 10^{-3} [/tex] = 17.34 Ω
From the above formula for [tex]I_{L}[/tex]:
[tex]I_{L} = \frac{240\angle0}{13 + j17.34 }[/tex]
[tex]I_{L}[/tex] = (6.64 - j8.86) A = [tex]11.07\angle-53.14^{\circ}[/tex] A
[tex]i_{L}(t)[/tex] = [tex]\sqrt{2}\times 11.07cos(2\pi \times 60t - 53.14)[/tex] A
[tex]i_{L}(t)[/tex] = 15.65cos(376.99t - 53.14)A
