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Find an equation of the tangent line to the curve at the given point.y = 7x2 − x3, (1, 6)y = Correct: Your answer is correct. Illustrate by graphing the curve and the tangent line on the same screen.

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sqdancefan

Answer:

  y = 11(x -1) +6

Step-by-step explanation:

The slope at the given point is ...

  y' = 14x -3x^2 = 14(1) -3(1^2) = 11

Then the point-slope equation for the line can be written as ...

  y = m(x -h) +k . . . . . . for slope m at point (h, k)

  y = 11(x -1) +6

Ver imagen sqdancefan