Explanation:
It is given that,
Mass of the artillery shell, m = 1100 kg
Acceleration of he shell, [tex]a=2.4\times 10^4\ m/s^2[/tex]
(a) The magnitude of force exerted on the shell can be calculated using Newton's second law of motion as :
F = ma
[tex]F=1100\ kg\times 2.4\times 10^4\ m/s^2[/tex]
F = 26400000 N
or
[tex]F=2.6\times 10^7\ N[/tex]
(b) The magnitude of the force exerted on the ship by the artillery shell will be same but the direction is opposite as per Newton's third law of motion. i.e [tex]2.6\times 10^7\ N[/tex]
