Respuesta :
Answer:
#include <iostream>
using namespace std;
void hexadecimal(int dec)
{
char hexa[100];// character array to store hexadecimal number.
int i = 0;
while(dec!=0)
{
int digit = 0;
digit = dec % 16;// storing remainder.
if(digit < 10)//condition
{
hexa[i] = digit + 48;//storing digit according to ascii values.
i++;
}
else
{
hexa[i] = digit + 55; //storing respective character according to ascii values..
i++;
}
dec = dec/16;
}
cout<<"The corresponding Hexadecimal number is :- ";
for(int j=i-1; j>=0; j--)// printing in reverse order .
cout << hexa[j];
cout<<endl;
}
void Binary(int dec)
{
int bin[32];// integer array to store binary values.
int i = 0;
while (dec > 0) {
bin[i] = dec % 2;// storing remainder
dec = dec / 2;
i++;
}
cout<<"The corresponding Binary number is :- ";
for (int j = i - 1; j >= 0; j--) // printing in reverse order
cout << bin[j];
cout<<endl;
}
void Octal(int dec)
{
int oct[100];// integer array to store octal values.
int i = 0;
while (dec != 0) {
oct[i] = dec % 8;// storing remainder
dec = dec / 8;
i++;
}
cout<<"The corresponding Octal number is :- ";
for (int j = i - 1; j >= 0; j--) // printing in reverse order
cout << oct[j];
cout<<endl;
}
int main() {
int d,bin,oct,hex;
cout<<"Enter decimal number"<<endl;
cin>>d;//taking input.
Binary(d);
Octal(d);
hexadecimal(d);
return 0;
}
OUTPUT:-
Enter decimal number
10
The corresponding Binary number is :- 1010
The corresponding Octal number is :- 12
The corresponding Hexadecimal number is :- A
Enter decimal number
256
The corresponding Binary number is :- 100000000
The corresponding Octal number is :- 400
The corresponding Hexadecimal number is :- 100
Explanation:
I have built 3 function of type void Hexadecimal,Binary,Octal all the functions take decimal integer as argument.They print their respective number after conversion.
So main approach is that :-
1.Take an array to store the digit on dividing.
2.Find the remainder on dividing it by corresponding number (for ex:- if binary divide by 2).
3.Store each remainder in the array.
4.Divide the number until it becomes 0.
5.Print the array in reverse.
