Answer:
[tex]F'(-3,-5),G'(-2,-5),H'(-2,-2)[/tex]
Step-by-step explanation:
The given points are: F(−5,−3) G(−5,−2) H(−2,−2)
The mapping for reflection in the line [tex]y=x[/tex] is [tex](x,y)\to (y,x)[/tex].
We just have to swap the coordinates of the preimage to obtain the image
[tex]F(-5,-3)\to F'(-3,-5)[/tex].
[tex]G(-5,-2)\to G'(-2,-5)[/tex].
[tex]H(-2,-2)\to H'(-2,-2)[/tex].
Therefore the image points are
[tex]F'(-3,-5),G'(-2,-5),H'(-2,-2)[/tex]
