The combustion of titanium with oxygen produces titanium dioxide: Ti (s) + O2 (g) → TiO2 (s) When 2.060 g of titanium is combusted in a bomb calorimeter, the temperature of the calorimeter increases from 25.00°C to 91.60°C. In a separate experiment, the heat capacity of the calorimeter is measured to be 9.84 kJ/K. The heat of reaction for the combustion of a mole of Ti in this calorimeter is __________ kJ/mol.

Respuesta :

Answer : The heat of reaction for the combustion of a mole of Ti in this calorimeter is, -31395.53 kJ/mol.

Explanation :

First we have to calculate the heat of reaction.

[tex]q=m\times C\Delta T=m\times C \times (T_2-T_1)[/tex]

where,

q = heat

C = heat capacity of the calorimeter = [tex]9.84kJ/K=9.84kJ/^oC[/tex]

m = mass of titanium = 2.060 g

[tex]T_2[/tex] = final temperature = [tex]91.60^oC[/tex]

[tex]T_1[/tex] = initial temperature = [tex]25.00^oC[/tex]

Now put all the given values in the above expression, we get:

[tex]q=2.060g\times (9.84kJ/^oC)\times (91.60-25.00)^oC[/tex]

[tex]q=1350.008kJ[/tex]

Now we have to calculate moles of titanium.

[tex]\text{Moles of }Ti=\frac{\text{Mass of }Ti}{\text{Molar mass of }Ti}=\frac{2.060g}{47.87g/mole}=0.043moles[/tex]

Now  we have to calculate the heat of reaction for the combustion of a mole of Ti in this calorimeter.

[tex]\Delta H_{rxn}=-\frac{q}{n}[/tex]

where,

[tex]\Delta H_{rxn}[/tex] = enthalpy of reaction = ?

q = heat of reaction = 1350.008 kJ

n = moles of ti = 0.043 mole

Now put all the given values in above expression, we get:

[tex]\Delta H_{rxn}=-\frac{1350.008kJ}{0.043mole}=-31395.53kJ/mole[/tex]

Therefore, the heat of reaction for the combustion of a mole of Ti in this calorimeter is, -31395.53 kJ/mol.

Note: C = 9.84 kJ / K = 9.84 kJ / ° C

         m = 2,060 g

        T2 = 91.60 ° C

         T1 = 25.00 ° C

Asked: ΔHrxn?

Answer: First, look for q first with the formula:

              => q = m x CΔT

              => q = m x C x (T2 - T1)

              => q = 2,060 g x 9.84kJ / ° C x (91.60 - 25.00) ° C

              => q = 1350,008kJ

Second, look for moles of Ti with the formula:

              => n = Ti mass / Ti molar mass

              => n = 2,060 g / 47.87 g / mol

              => n = 0.043 mol

Third, look for ΔHrxn with the formula:

              => ΔHrxn = - (q / n)

              => ΔHrxn = - (1350,008kJ / 0.043 mol)

              => ΔHrxn = -31395,53 kJ / mol

Thus, the reaction heat for burning one mole of Ti in a calorimeter is -31395.53 kJ / mol.

Further Explanation

Thermochemistry is a branch of chemistry that deals with the reciprocal relationship of heat with chemical reactions or with changes in physical conditions. In general, thermochemistry is the application of thermodynamics to chemistry. Thermochemistry is a synonym of chemical thermodynamics.

The main purpose of thermochemistry is the formation of criteria for the determination of the likelihood of occurrence or spontaneity of the transformation needed. In this way, thermochemistry is used to estimate the energy changes that occur in the following processes:

  • chemical reaction
  • phase change
  • formation of solution  

Thermodynamics is the physics of energy, heat, work, entropy and the spontaneous process. Thermodynamics is closely related to statistical mechanics where the thermodynamic relationship originates. In systems where the process of change of form or energy exchange occurs, classical thermodynamics is not related to the kinetics of the reaction (the speed of a reaction process takes place). Therefore, the use of the term "thermodynamics" usually refers to equilibrium thermodynamics, which is the main concept of a quasi-static process, which is idealized. Meanwhile, time-dependent thermodynamics is non-equilibrium thermodynamics.

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Details

Grade: High School

Subject: Chemistry

keywords: Thermochemistry