Answer:
[tex]\boxed{\text{29.5 mL}}[/tex]
Explanation:
The temperature and amount of gas are constant, so we can use Boyle’s Law.
[tex]p_{1}V_{1} = p_{2}V_{2}[/tex]
Data:
[tex]\begin{array}{rcrrcl}p_{1}& =& \text{1.00 atm}\qquad & V_{1} &= & \text{1.81L} \\p_{2}& =& \text{40.0}\qquad & V_{2} &= & ?\\\end{array}[/tex]
Calculations:
[tex]\begin{array}{rcl}1.00 \times 1.81 & =& 40.0V_{2}\\1.180 & = & 40.0V_{2}\\V_{2} & = &\textbf{0.0295 L = 29.5 mL}\\\end{array}\\\text{The volume of the gas is } \boxed{\textbf{29.5 mL}}[/tex]
