Answer:
Explanation:
(NH4)3 PO4 +NaOH arrow Na3PO4 +3NH3 +3H2O
Start by seeing what happens with the Na. You need 3 on the left, so put a 3 in front of NaOH
(NH4)3 PO4 +3NaOH arrow Na3PO4 +3NH3 +3H2O Next work with the nitrogens. YOu have 3 on the left and 3 on the right, so they are OK. Next Go to the stray oxygens.
You have 3 on left in (NaOH) and three on the right in 3H2O so they are fine as well. The last thing you should look at are hydrogens.
There are 12 + 3 on the left which is 15. There are 9 (in 3NH3) and 6 more in the water. They seem fine.
Why didn't I do something with the PO4^(-3)? The reason is a deliberately stayed away from them and balanced everything else. Since they were untouched with 1 on the left and 1 on the right, they are balanced.
Species Na H O N PO4
Left 3 15 3 3 1
Right 3 15 3 3 1
Answer:
(NH₄)₃PO₄ + 3NaOH ⟶ Na₃PO₄ + 3NH₃ + 3H₂O
Explanation:
Your unbalanced equation is
(NH₄)₃PO₄ + NaOH ⟶ Na₃PO₄ + NH₃ + H₂O
A method that usually works for balancing by inspection is
1. Pick the most complicated-looking formula [(NH₄)₃PO₄].
Put a 1 in front of it.
1(NH₄)₃PO₄ + NaOH ⟶ Na₃PO₄ + NH₃ + H₂O
2. Balance N.
We have fixed 3N on the left. We need 3N on the right.
Put a 3 in front of NH₃.
1(NH₄)₃PO₄ + NaOH ⟶ Na₃PO₄ + 3NH₃ + H₂O
3. Balance P.
We have fixed 1P on the left. We need 1P on the right.
Put a 1 in front of Na₃PO₄.
1(NH₄)₃PO₄ + NaOH ⟶ 1Na₃PO₄ + 3NH₃ + H₂O
4. Balance Na
We have fixed 3Na on the right. we need 3Na on the left.
Put a 3 in front of NaOH.
1(NH₄)₃PO₄ + 3NaOH ⟶ 1Na₃PO₄ + 3NH₃ + H₂O
5. Balance O.
We have fixed 7O on the left and 4O on the right. We need three more O atoms on the right.
Put a 3 in front of H₂O.
1(NH₄)₃PO₄ + 3NaOH ⟶ 1Na₃PO₄ + 3NH₃ + 3H₂O
All species have a coefficient. The equation should now be balanced.
6. Check that all atoms are balanced
[tex]\begin{array}{ccc}\textbf{Atom} & \textbf{On the left} & \textbf{On the right}\\\text{N} & 3 & 3\\\text{H} & 15 & 15\\\text{P} & 1 & 1\\\text{O} & 7 & 7\\\text{Na} & 3 & 3\\\end{array}[/tex]
The balanced equation is
(NH₄)₃PO₄ + 3NaOH ⟶ Na₃PO₄ + 3NH₃ + 3H₂O
