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Three batteries are connected in series so that the total voltage is 54 volts. The voltage of the first battery is twice the voltage of the second and 1/3 the voltage of the third battery. Find the actual voltage of each battery.

Respuesta :

Answer:

[tex]v_1 = 12 volts[/tex]

[tex]v_2 = 6 volts[/tex]

[tex]v_3 = 36 volts[/tex]

Explanation:

As we know that all the batteries are in series

so the net voltage of all three batteries is given as

[tex]V = v_1 + v_2 + v_3[/tex]

now we know that

[tex]v_1 = 2v_2[/tex]

[tex]v_1 = \frac{1}{3}v_3[/tex]

now plug in all the values in it

[tex]54 = v_1 + \frac{v_1}{2} + 3v_1[/tex]

[tex]54 = 4.5 v_1[/tex]

[tex]v_1 = 12 volts[/tex]

now we have

[tex]v_2 = 6 volts[/tex]

[tex]v_3 = 36 volts[/tex]