Answer:
[tex]v_1 = 12 volts[/tex]
[tex]v_2 = 6 volts[/tex]
[tex]v_3 = 36 volts[/tex]
Explanation:
As we know that all the batteries are in series
so the net voltage of all three batteries is given as
[tex]V = v_1 + v_2 + v_3[/tex]
now we know that
[tex]v_1 = 2v_2[/tex]
[tex]v_1 = \frac{1}{3}v_3[/tex]
now plug in all the values in it
[tex]54 = v_1 + \frac{v_1}{2} + 3v_1[/tex]
[tex]54 = 4.5 v_1[/tex]
[tex]v_1 = 12 volts[/tex]
now we have
[tex]v_2 = 6 volts[/tex]
[tex]v_3 = 36 volts[/tex]