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A coin of mass .005 kg dropped from a height of 3 m. How much potential energy does it have right before it hits the ground? Assume there is no air resistance. Acceleration due to gravity is g=9.8 m/s2

Respuesta :

MathPhys

Answer:

0 J

Explanation:

Gravitational potential energy is:

PE = mgh

where m is mass, g is acceleration due to gravity, and h is the height.

Right before the coin hits the ground, its height above the ground is 0 m, so the potential energy is:

PE = mgh

PE = (0.005 kg) (9.8 m/s²) (0 m)

PE = 0 J

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