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Identify the Brønsted-Lowry acid, the Brønsted-Lowry base, the conjugate acid, and the conjugate base in each reaction: (a) (CH3)3N(aq)+H2O(l)⇌(CH3)3NH+(aq)+OH−(aq) (b) HNO3(aq)+H2O(l)⇌H3O+(aq)+NO3−(aq)

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InesWalston

Answer: A. Bronsted Lowery acid: H2O

Bronsted Lowery base: (CH3)3N

Conjugate acid: (CH3)3NH+

Conjugate base: OH-

B. Acid: HNO3

Base: H2O

Conjugate acid: H3O+

Conjugate base: NO3-

Explanation:

Bronsted Lowery acid is proton donor and proton acceptor is base.

And Conjugate acid-base pairs are differed by one proton

Answer :

(a) [tex](CH_3)_3NH^+[/tex] and [tex]OH^-[/tex] are conjugate acid and base respectively.

(b) [tex]H_3O^+[/tex] and [tex]NO_3^-[/tex] are conjugate acid and base respectively.

Explanation :

According to the Bronsted Lowry concept, Bronsted Lowry-acid is a substance that donates one or more hydrogen ion in a reaction and Bronsted Lowry-base is a substance that accepts one or more hydrogen ion in a reaction.

Or we can say that, conjugate acid is proton donor and conjugate base is proton acceptor.

(a) The given equilibrium reaction is,

[tex](CH_3)_3N(aq)+H_2O(l)\rightleftharpoons (CH_3)_3NH^+(aq)+OH^-(aq)[/tex]

In this reaction, [tex]H_2O[/tex] is an acid that donate a proton or hydrogen to [tex](CH_3)_3N[/tex] base and it forms [tex](CH_3)_3NH^+[/tex] and [tex]OH^-[/tex] are conjugate acid and base respectively.

(b) The given equilibrium reaction is,

[tex]HNO_3(aq)+H_2O(l)\rightleftharpoons NO_3^-(aq)+H_3O^+(aq)[/tex]

In this reaction, [tex]HNO_3[/tex] is an acid that donate a proton or hydrogen to [tex]H_2O[/tex] base and it forms [tex]H_3O^+[/tex] and [tex]NO_3^-[/tex] are conjugate acid and base respectively.