Answer:
52.9 N, 364.7 N
Explanation:
First of all, we need to resolve both forces along the x- and y- direction. We have:
- Force A (178 N)
[tex]A_x = (178 N)(cos 41.7^{\circ})=132.9 N\\A_y = (178 N)(sin 41.7^{\circ})=118.4 N[/tex]
- Force B (259 N)
[tex]B_x = (259 N)(cos 108^{\circ})=-80.0 N\\B_y = (259 N)(sin 108^{\circ})=246.3 N[/tex]
So the x- and y- component of the total force acting on the block are:
[tex]R_x = A_x + B_x = 132.9 N - 80.0 N =52.9 N\\R_y = A_y + B_y = 118.4 N +246.3 N = 364.7 N[/tex]
