Answer:
[tex]f(g(2))=3(2+h)^{2} +2(2+h)-4[/tex]
Step-by-step explanation:
we have
[tex]f(x)=3x^{2} +2x-4[/tex]
[tex]g(x)=x+h[/tex]
we know that
[tex]f(g(x))=3(x+h)^{2} +2(x+h)-4[/tex]
To determine [tex]f(g(2))[/tex]
substitute the value of x=2 in the function
so
[tex]f(g(2))=3(2+h)^{2} +2(2+h)-4[/tex]