Graph a line with a slope of -3 that contains the point (4,-2)

Start from the point (4,-2) by going to the right of the origin 4 units and down 2 units. Then go down three and to the right one. The second point is (5,-3) Then, draw a line going from (4,-2) to (5,-3). If it helps, make another point by going 3 up and one to the left of (4,-2).

Step-by-step explanation:

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Adetunmbiadekunle Adetunmbiadekunle · Answer 2 · 2021-10-15T12:21:17+02:00

The graph a line with a slope of -3 that contains the point (4,-2) is shown below

The slope, m = -3

The point (x₁, y₁) = (4, -2)

That is, x₁ = 4, y₁ = -2

The point-slope form of the equation of a line is shown below:

y - y₁ = m(x - x₁)

Substitute m = -3, x₁ = 4, y₁ = -2 into the equation y - y₁ = m(x - x₁)

y - (-2) = -3(x - 4)

y + 2 = -3x + 12

Subtract 2 from both sides

y + 2 - 2 = -3x + 12 - 2

y = -3x + 10

This is of the form y = mx + c

where the slope, m = -3

and the y-intercept, c = 10

Plot the graph of the line with slope m = -3 and y-intercept c = 10

The graph of the line is plotted below

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