Answer:
Total electrostatic energy of the system, PE = U = [tex]13.82\times 10^{-19} J[/tex]
Given:
radius of sphere, r = [tex]10^{- 10}m[/tex]
electronic charge, e = [tex]1.6\times 10^{-19} C[/tex]
Solution:
The total electrostatic energy of the system for a uniformly spread charge e on the sphere is given by the potential energy of the system as:
PE = U = [tex]\frac{3}{5}\frac{q^{2}}{4\pi \epsilon_{o}r}[/tex]
The above eqn can also be written as:
PE = U = [tex]\frac{3}{5}\frac{e^{2}}{4\pi \epsilon_{o}r}[/tex]
Putting the values in the above eqn:
PE = U = [tex]\frac{3}{5}\frac{(1.6\times 10^{-19})^{2}}{4\pi \times 8.85\times 10^{-12}\times 10^{-10}}[/tex]
PE = U = [tex]13.82\times 10^{-19} J[/tex]
