jax40
contestada

Find the slope of the line that passes through each pair of points (-3/4,5),(5/4,2)

Respuesta :

Answer:

m=-3/2

Step-by-step explanation:

m=slope

m = (y2-y1)/(x2-x1)

first point: (-3/4,5)

second point: (5/4,2)

m= (2-5)/(5/4-(-3/4))

m= -3/2

[tex]\bf (\stackrel{x_1}{-\frac{3}{4}}~,~\stackrel{y_1}{5})\qquad (\stackrel{x_2}{\frac{5}{4}}~,~\stackrel{y_2}{2}) \\\\\\ \stackrel{slope}{m}\implies \cfrac{\stackrel{rise} {\stackrel{y_2}{2}-\stackrel{y1}{5}}}{\underset{run} {\underset{x_2}{\frac{5}{4}}-\underset{x_1}{(-\frac{3}{4})}}}\implies \cfrac{-3}{\frac{5}{4}+\frac{3}{4}}\implies \cfrac{-3}{\frac{5+3}{4}}\implies\cfrac{-3}{\frac{8}{4}}\implies \cfrac{-3}{2}[/tex]