Answer:
The angle of the corresponding refracted ray is 34.84°
Explanation:
Given that,
Refractive index of water n= 1.33
Refractive index of glass n= 1.52
Incident angle = 30.0°
We need to calculate the refracted angle
Using formula of Snell's law
[tex]n_{i}\sin i=n_{r}\sin r[/tex]
Put the value into the formula
[tex]\sin r=\dfrac{n_{i}\sin i}{n_{r}}[/tex]
[tex]\sin r=\dfrac{1.52\times\sin30}{1.33}[/tex]
[tex]\sin r=0.5714[/tex]
[tex]r=sin^{-1}0.5714[/tex]
[tex]r = 34.84^{\circ}[/tex]
Hence, The angle of the corresponding refracted ray is 34.84°
