Answer:
14.48 N
Explanation:
We have given the diameter of the specimens d = 15 mm ,so radius [tex]r=\frac{15}{2}=7.5 cm[/tex]
Area of the specimen [tex]A=\pi r^2=3.14\times 0.075^2=0.01766m^2[/tex]
The maximum tensile strength = 820 [tex]N/m^2[/tex]
We know that [tex]maximu\ tensile\ strength =\frac{maximum\ tensile\ force}{Area}[/tex]
[tex]820=\frac{maximu\ tensile\ force}{0.01766}=14.48N[/tex]
