Explanation:
It is given that,
Velocity of arrow, v = 32 m/s
Height above ground, h = 295 m
Let t is the time taken by arrow in air. It is given by :
[tex]h=ut+\dfrac{1}{2}at^2[/tex]
a = g
Initially, u = 0
[tex]t=\sqrt{\dfrac{2h}{g}}[/tex]
[tex]t=\sqrt{\dfrac{2\times 295}{9.8}}[/tex]
t = 7.75 seconds
Let it land at a distance of d. It is given by :
[tex]d=v\times t[/tex]
[tex]d=32\times 7.75[/tex]
d = 248 meters
Hence, this is the required solution.
