Answer:
2 mT perpendicularly inwards to the plane of paper
Explanation:
i1 = 8 A
i2 = 12 A
Let 8 A is in upward direction and 12 A is in downward direction
The magnetic field at point P due to 8 A current
[tex]B_{1}=\frac{\mu _{0}}{4\pi }\frac{2i_{1}}{r}[/tex]
[tex]B_{1}=10^{-7}\times \frac{2\times 8}{0.002}[/tex]
B1 = 8 x 10^-4 T Perpendicular inwards to the plane of paper
The direction of magnetic field is calculated by the Maxwell's right hand grip rule.
The magnetic field at point P due to 12 A current
[tex]B_{2}=\frac{\mu _{0}}{4\pi }\frac{2i_{2}}{r}[/tex]
[tex]B_{2}=10^{-7}\times \frac{2\times 12}{0.002}[/tex]
B1 = 12 x 10^-4 T Perpendicular inwards to the plane of paper
The direction of magnetic field is calculated by the Maxwell's right hand grip rule.
Theresultant magnetic field at point P
B = B1 + B2 = ( 8 + 12) x 10^-4 = 20 x 10^-4 T
B = 20 x 10^-4 T = 2 mT perpendicularly inwards to the plane of paper
