Answer:
pressure of the gas after the expansion is 1795.238 Pa
Explanation:
adiabatic expansion W(+) - ideal gas:
deriving (1):
⇒ PdV + VdP = RndT
⇒ PdV = RndT - VdP
being the T constant ⇒ dT = 0
⇒ PdV = - VdP............(3)
(3) in (1):
⇒ W = ∫ (- VdP )
⇒ W = - V ∫dP
⇒ W = - V * ( P2 - P1 )
⇒ P2 = - ( W / V ) + P1
⇒ P2 = - ( 1480 J / 2,1 m³ ) + 2.5 E3 J /m³
⇒ P2 = - 704.762 J/m³ + 2.5 E3 J/m³
⇒ P2 = 1795.238 Pa