Respuesta :
Answer:
Yes, there will be collision.
Explanation
Initial relative velocity u = 34-5.4 = 28.6 m/s
required final relative velocity v = 0
Acceleration , suppose be a .
Distance traveled =d = 160 m
Using the formula for relative motion,
v² - u² = 2as
0 - 28.6²=2as
a = - 2.55 m s⁻².
Since this required value is more than maximum braking deceleration so , there will be collision.
Answer:
Yes there will be a collision.
Explanation:
We shall use the relative motion between the 2 cars to solve
Relative speed of Sue with respect to slow moving van is
[tex]V_{r}=V_{sue}-V_{van}\\\\V_{r}=34-5.40=28.6m/s[/tex]
Now in order to stop this vehicle the distance it requires to stop shall be calculated by third equation of kinematics as
[tex]v^{2}=u^{2}+2as[/tex]
since the finally the car shall stop thus v = 0 m/s
Applying values in the above equation and solving for 's' we get
[tex]0=28.6^{2}+2\times -1.90\times s\\\\\therefore s=\frac{28.6^{2}}{2\times 1.90}\\\\s=215.25m[/tex]
Since distance required to stop is greater than available distance of 160 m thus the two cars shall collide.
