Answer:
Option 2 - square root 5, 5 over 2, 2.71 repeating 71, 2 and 3 over 4.
Step-by-step explanation:
Given : Numbers 2.71 repeating 71, 2 and 3 over 4, square root 5, 5 over 2
To find : Order the set of numbers from least to greatest ?
Solution :
First we write numbers in one form i.e. in decimals,
2.71 repeating 71 = [tex]2.7171....[/tex]
2 and 3 over 4 = [tex]2\frac{3}{4}=\frac{11}{4}=2.75[/tex]
square root 5 = [tex]\sqrt{5}=2.2360....[/tex]
5 over 2 = [tex]\frac{5}{2}=2.5[/tex]
Arranging from least to greatest,
[tex]2.2360.. < 2.5 < 2.7171.. < 2.75[/tex]
or [tex]\sqrt{5}< \frac{5}{2} < 2.7171.. < 2\frac{3}{4}[/tex]
or square root 5, 5 over 2, 2.71 repeating 71, 2 and 3 over 4.
Therefore, Option 2 is correct.
