Respuesta :
Answer:
14848
Step-by-step explanation:
These are the terms of a geometric sequence with n th term
[tex]a_{n}[/tex] = a[tex]r^{n-1}[/tex]
where a is the first term and r the common ratio
here a = 29 and r = 58 ÷ 29 = 116 ÷ 58 = 2, hence
[tex]a_{10}[/tex] = 29 × [tex]2^{9}[/tex] = 29 × 512 = 14848
The first term of the sequence is 29 and the common ratio is 2. Then the tenth number of the sequence is 14,848.
What are sequence and series?
A sequence is a list of elements that have been ordered in a sequential manner, such that members come either before or after.
Given
The first three terms of a sequence are shown.
29, 58, 116, and so on.
The sequence can be represented as
[tex]\rm 29*2^1, 29* 2^2, \ and \ so \ on[/tex]
This can be generalized as
[tex]\rm a_n = 29*2^{n-1}[/tex]
Where 29 is the first term and 2 is the common ratio.
The 10th term will be
[tex]\rm a_{10} = 29*2^{10-1}\\\\a_{10} = 29*2^{9}\\\\a_{10} = 29*512\\\\a_{10} = 14848[/tex]
Thus, the tenth term of the sequence is 14,848.
More about the sequence link is given below.
https://brainly.com/question/21961097