Answer:
The final temperature is 85.86°C.
Explanation:
Given that,
Mass of tea = 200 g
Mass of glass = 150 g
Initial temperature = 25°C
We need to calculate the final temperature
When equilibrium is reached, assuming no heat flows to the surroundings
So,
[tex]Q_{glass}+Q_{tea}=0[/tex]
[tex]m_{g}C\Delta T+m_{g}C\Delta T=0[/tex]
We know that,
Specific heat of tea = 1.00 cal/gm° C
Specific heat of tea = 0.20 cal/gm° C
Put the value into the formula
[tex]150\times0.20\times(T_{2}-T_{1})+200\times1.00\times(T_{2}-T_{1})[/tex]
[tex]30T_{2}-30T_{1}+200T_{2}-200T_{1}=0[/tex]
[tex]30T_{2}+200T_{2}=30T_{1}+200T_{1}[/tex]
Put the value of initial temperature
[tex]T_{2}=\dfrac{30\times25+200\times95}{230}[/tex]
[tex]T_{2}=85.86^{\circ}C[/tex]
Hence, The final temperature is 85.86°C.
