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A 4-stroke Diesel engine with a displacement of Vd = 2.5x10^-3m^3 produces a mean effective pressure of 6.4 bar at the speed of 2000 rpm. Calculate the power developed by the engine at this operating condition.

Respuesta :

Answer:

The power developed by engine is 167.55 KW

Explanation:

Given that

[tex]V_d=2.5\times 10^{-3} m^3[/tex]

Mean effective pressure = 6.4 bar

Speed = 2000 rpm

We know that power is the work done per second.

So

[tex]P=6.4\times 100\times 2.5\times 10^{-3}\times \dfrac{2\pi \times2000}{120}[/tex]

We have to notice one point that we divide by 120 instead of 60, because it is a 4 cylinder engine.

P=167.55 KW

So the power developed by engine is 167.55 KW

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