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The pressure of an ideal gas is doubled during a process in which the energy given up as heat by the gas equals the work done on the gas. As a result, the volume is : (A) doubled (B) halved (C) unchanged

Respuesta :

Answer:

[tex]V' = \frac{V}{2}[/tex]

So volume is halved

Explanation:

As we know that heat energy given to the gas is equal to the work done

so as per first law of thermodynamics we know that

[tex]\Delta Q = W + \Delta U[/tex]

now we know that

[tex]\Delta Q = W[/tex]

so we have

[tex]\Delta U = 0[/tex]

so we have temperature of the gas is constant

so it is an isothermal process

so here we can say

[tex]PV = constant[/tex]

so here we can say

[tex]P(V) = (2P)V'[/tex]

so we have

[tex]V' = \frac{V}{2}[/tex]

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