Respuesta :

Answer:

Explanation:

Energy of electron in n = 4 state

= - 13.6/4² =- 0.85 eV

So energy needed to extract it from atom = .85 eV.

The energy needed for the ionization of hydrogen atom will be [tex]\rm E=0.85\ eV[/tex]

What will be the ionization energy of the Hydrogen Atom?

The formula for the ionization of the hydrogen atom will be given as

[tex]\rm E=\dfrac{13.6}{n^2}[/tex]

Here we have n=4 so

[tex]\rm E=\dfrac{13.6}{4^2}[/tex]

[tex]\rm E=\dfrac{13.6}{16} =0.85\ eV[/tex]

Thus the energy needed for the ionization of hydrogen atoms will be [tex]\rm E=0.85\ eV[/tex]

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