Respuesta :
Answer:
Explanation:
Energy of electron in n = 4 state
= - 13.6/4² =- 0.85 eV
So energy needed to extract it from atom = .85 eV.
The energy needed for the ionization of hydrogen atom will be [tex]\rm E=0.85\ eV[/tex]
What will be the ionization energy of the Hydrogen Atom?
The formula for the ionization of the hydrogen atom will be given as
[tex]\rm E=\dfrac{13.6}{n^2}[/tex]
Here we have n=4 so
[tex]\rm E=\dfrac{13.6}{4^2}[/tex]
[tex]\rm E=\dfrac{13.6}{16} =0.85\ eV[/tex]
Thus the energy needed for the ionization of hydrogen atoms will be [tex]\rm E=0.85\ eV[/tex]
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