Answer:
[tex] 540.68[/tex] ohm
Explanation:
R = resistance of the resistor = 74.31 ohm
f = source frequency = 60 Hz
C = Capacitance of the capacitor = 4.11 x 10⁻⁶ F
[tex]X_{c}[/tex] = capacitive reactance of capacitor
capacitive reactance of capacitor is given as
[tex]X_{c} = \frac{1}{2\pi fC}[/tex]
[tex]X_{c} = \frac{1}{2(3.14)(60)(4.11\times 10^{-6})}[/tex]
[tex]X_{c} = 645.725[/tex] ohm
L = Inductance of inductor = 293.39 mH = 0.29239 H
[tex]X_{L}[/tex] = Inductive reactance of Inductor
Inductive reactance of Inductor is given as
[tex]X_{L} = 2\pi fL[/tex]
[tex]X_{L} = 2(3.14) (60) (0.29239)[/tex]
[tex]X_{L} = 110.173[/tex] ohm
Impedance is given as
[tex]Z = \sqrt{R^{2} + (X_{L} - X_{c})^{2}}[/tex]
[tex]Z = \sqrt{74.31^{2} + (110.173 - 645.725)^{2}}[/tex]
[tex]Z = \sqrt{74.31^{2} + (110.173 - 645.725)^{2}}[/tex]
[tex]Z = 540.68[/tex] ohm
