Answer:
a) 107.1875 Hz
b) 214.375 Hz
c) 321.5625 Hz
Explanation:
L = length of the open organ pipe = 1.6 m
v = speed of sound = 343 m/s
f = fundamental frequency
fundamental frequency is given as
[tex]f = \frac{v}{2L}[/tex]
inserting the values
[tex]f = \frac{343}{2(1.6)}[/tex]
[tex]f = \frac{343}{2(1.6)}[/tex]
[tex]f = 107.1875[/tex] Hz
b)
first overtone is given as
f' = 2f
f' = 2 (107.1875)
f' = 214.375 Hz
c)
first overtone is given as
f'' = 3f
f'' = 3 (107.1875)
f'' = 321.5625 Hz
