Answer:
0.042 m
Explanation:
L = length of the copper wire = 7 m
N = Number of turns in the current loop
B = magnetic field at the center = 0.006582 T
i = current flowing through the wire = 4.092 A
r = radius of the coil
length of the copper wire is given as
L = 2πrN
7 = 2πrN
rN = 1.115
[tex]N = \frac{1.115}{r}[/tex] eq-1
Magnetic field at the center of the coil is given
[tex]B = \frac{\mu _{o}}{4\pi } \left ( \frac{2\pi Ni}{r} \right )[/tex]
[tex]0.006582 = (10^{-7}) \left ( \frac{2(3.14)(1.115)(4.092)}{r^{2}} \right )[/tex]
r = 0.021 m
diameter is given as
d = 2r
d = 2 (0.021)
d = 0.042 m
