Respuesta :

Answer:

49.19°

Explanation:

θ₁ = Angle of incidence

θ₂ = Angle of refraction = 34.7°

n₁ = Refractive index of air = 1.0003

n₂ = Refractive index of water = 1.33

From Snell's Law

[tex]\frac{sin\theta_2}{sin\theta_1}=\frac{n_1}{n_2}\\\Rightarrow sin\theta_1=\frac{sin\theta_2}{\frac{n_1}{n_2}}\\\Rightarrow sin\theta_1=\frac{sin34.7}{\frac{1.0003}{1.33}}\\\Rightarrow \theta_1=sin^{-1}\frac{sin34.7}{\frac{1.0003}{1.33}}\\\Rightarrow \theta_1=49.19^{\circ}[/tex]

In order to find the angle of sun above horizon we have to subtract the angle

90 - 49.19 = 40.81

The sun is at an angle of 40.81° above the horizon.

The Sun is at an angle of 40.81° above the horizon.

What is Snell's law?

It states that the ratio of sine of angle of incidence and angle of refraction is equal to the refractive index of second medium to the first medium.

sini/sinr = n₁/n₂

Given the angle of incidence is i, angle of refraction r =34.7° , n₁ = Refractive index of air = 1.0003 and n₂ = Refractive index of water = 1.33

Substituting the values we get,

sin i= sin 34.7/(1.003/1.33)

i = 49.19 degrees

The angle of Sun above horizon, we have

90° - 49.19° = 40.81°

Thus, the sun is at an angle of 40.81° above the horizon.

Learn more about Snell's law.

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