Respuesta :
Answer:
The inner diameter of the steam tube is 0.1185 m.
Explanation:
[tex]m=\rho \times A\times v=\frac{1}{V}\times A\times v[/tex]
m = mass flow rate
[tex]\rho [/tex] = density of the liquid
V=specific volume =[tex]\frac{1}{\rho }[/tex]
v = velocity of the liquid
A = area of cross-section
Diameter of the cross-section = d = 2r
Given: m = 18 kg/s, v = 60 m/s,A=?, [tex]V = 0.036793 m^3/kg[/tex]
[tex]18 kg/s=\frac{1}{0.036793 m^3/kg}\times A\times 60 m/s[/tex]
[tex]A=0.0110379 m^2[/tex]
Area of the inner cross section = [tex]\pi r^2=\pi \frac{d^2}{4}[/tex]
[tex]\pi \frac{d^2}{4}=0.0110379 m^2[/tex]
d = 0.1185 m
The inner diameter of the steam tube is 0.1185 m.
