Answer:
[tex]- 2[/tex] cm
Explanation:
[tex]h_{o}[/tex] = height of the object = 6 cm
[tex]d_{o}[/tex] = distance of the object from the lens = 16 cm
[tex]f[/tex] = focal length of the lens = 4 cm
[tex]d_{i}[/tex] = image distance
using the lens equation
[tex]\frac{1}{d_{o}} + \frac{1}{d_{i}} = \frac{1}{f}[/tex]
[tex]\frac{1}{16} + \frac{1}{d_{i}} = \frac{1}{4}[/tex]
[tex]d_{i} = \frac{16}{3}[/tex] cm
[tex]h_{i}[/tex] = height of the image
Using the equation
[tex]\frac{h_{i}}{h_{o}} = \frac{- d_{i}}{d_{o}}[/tex]
[tex]\frac{h_{i}}{6} = \frac{- \frac{16}{3}}{16}[/tex]
[tex]h_{i} =-2[/tex] cm
