Answer:
15.92 A
Explanation:
L = length of the solenoid = 10 cm = 0.10 m
N = Number of turns of the solenoid = 2000
B = magnitude of magnetic field inside the solenoid = 0.4 T
i = magnitude of electric current in the solenoid
Magnetic field inside the solenoid is given as
[tex]B = \frac{\mu _{o}Ni}{L}[/tex]
[tex]0.4 = \frac{(12.56\times 10^{-7})(2000)i}{0.10}[/tex]
i = 15.92 A
